Ace 1z0-071 Certification with 305 Actual Questions [Q16-Q39]

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Ace 1z0-071 Certification with 305 Actual Questions

PASS Oracle 1z0-071 EXAM WITH UPDATED DUMPS

NO.16 Which two statements are true about INTERVAL data types?

The YEAR field in an INTERVAL YEAR TO MONTH column must be a positive value.

INTERVAL DAY TO SECOND columns support fractions of seconds.

INTERVAL YEAR TO MONTH columns only support monthly intervals within a single year.

INTERVAL YEAR TO MONTH columns support yearly intervals.

INTERVAL YEAR TO MONTH columns only support monthly intervals within a range of years.

The value in an INTERVAL DAY TO SECOND column can be copied into an INTERVAL YEAR TO MONTH column.

NO.17 You want to display the date for the first Monday of the next month and issue the following command:

What is the outcome?

In generates an error because rrrrshould be replaced by rrin the format string.

It executes successfully but does not return the correct result.

It executes successfully and returns the correct result.

In generates an error because TO_CHARshould be replaced with TO_DATE.

In generates an error because fmand double quotation marks should not be used in the format string.

NO.18 Examine the description of the EMPLOYYES table:

Which two statements will run successfully?

SELECT ‘The first-name is ‘ ‘ ‘ | | first_name | | ‘ ‘ ‘ FROM employees;

SELECT ‘The first-name is ‘ | | first_name | | ‘ ‘ FROM employees;

SELECT ‘The first-name is ‘ ‘ ‘ | | first_name | | ‘ ‘ ‘ ‘ FROM employees;

SELECT ‘The first-name is ‘ ‘ | | first_name | | ‘ ‘ FROM employees;

SELECT ‘The first-name is ‘ ‘ | | first_name | | ‘ ‘ ‘ FROM employees;

NO.19 Examine the structure of the SALES table. (Choose two.)

Examine this statement:
SQL > CREATE TABLE sales1 (prod_id, cust_id, quantity_sold, price)
AS
SELECT product_id, customer_id, quantity_sold, price
FROM sales
WHERE 1 = 2;
Which two statements are true about the SALES1 table?

It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.

It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.

It will not be created because of the invalid WHERE clause.

It is created with no rows.

It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.

NO.20 View the Exhibit and examine the structure of the PRODUCT_INFORMATION table.

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index? (Choose the best answer.)

SELECT product_id, UPPER(product_name)FROM product_informationWHERE
UPPER(product_name)=’LASERPRO’ OR list_price > 1000;

SELECT UPPER(product_name)FROM product_information;

SELECT UPPER(product_name)FROM product_informationWHERE product_id = 2254;

SELECT product_idFROM product_informationWHERE UPPER(product_name) IN (‘LASERPRO’,
‘CABLE’);

NO.21 In the EMPLOYEES table there are 1000 rows and employees are working in the company for more than 10 years.
Evaluate the following SQL statement:

What would be the result?

It executes successfully but no rows updated.

It executes successfully and updates the records of those employees who have been working in the company for more than 600 days.

It gives an error because multiple NVL functions are used in an expression.

It gives an error because NVL function cannot be used with UPDATE.

NO.22 View the Exhibit and examine the details of the PRODUCT_INFORMATION table. (Choose two.)

Evaluate this SQL statement:
SELECT TO_CHAR(list_price,’$9,999′)
From product_information;
Which two statements are true regarding the output? (Choose two.)

A row whose LIST_PRICE column contains value 11235.90 would be displayed as #######.

A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,123.

A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,124.

A row whose LIST_PRICE column contains value 11235.90 would be displayed as $1,123.

NO.23 View the Exhibit and examine the structure of CUSTOMERStable.

Evaluate the following query:

Which statement is true regarding the above query?

It produces an error because the condition on the CUST_CITYcolumn is not valid.

It produces an error because the condition on the CUST_FIRST_NAMEcolumn is not valid.

It produces an error because conditions on the CUST_CREDIT_LIMITcolumn are not valid.

It executes successfully.

NO.24 Examine this SQL statement
DELETE FROM employees e
WHERE EXISTS
(SELECT’ dummy’
FROM emp history
WHERE employee_ id= e. employee id);
Which two are true?

The subquery is not a correlated subquery.

The subquery is executed before the DELETE statement is executed.

All existing rows in the EMPLOYEES table are deleted,

The DELETE statement executes successfully even if the subquery selects multiple rows.

The subquery is executed for every row in the EMPLOYEES table.

NO.25 View the exhibit and examine the description of the DEPARTMENTSand EMPLOYEEStables.

You wrote this SQL statement to retrieve EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, for all employees:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?

The table prefix is missing for the column names in the SELECTclause.

The NATURAL JOINclause is missing the USINGclause.

The DEPARTMENTStable is not used before the EMPLOYEEStable in the FROMclause.

The EMPLOYEESand DEPARTMENTStables have more than one column with the same column name and data type.

NO.26 Evaluate the following SELECT statement and view the Exhibit to examine its output:

SELECT constraint_name, constraint_type, search_condition, r_constraint_name, delete_rule, status FROM user_constraints WHERE table_name = ORDERS
Which two statements are true about the output? (Choose two.)

In the second column, indicates a check constraint.

The STATUS column indicates whether the table is currently in use.

The R_CONSTRAINT_NAME column gives the alternative name for the constraint.

The column DELETE_RULE decides the state of the related rows in the child table when the corresponding row is deleted from the parent table.

NO.27 View the Exhibit and examine the structure of the ORDERS table. The ORDER_ID column is the PRIMARY KEY in the ORDERS table.

Evaluate the following CREATE TABLE command:
CREATE TABLE new_orders(ord_id, ord_date DEFAULT SYSDATE, cus_id)
AS
SELECT order_id.order_date,customer_id
FROM orders;
Which statement is true regarding the above command?

The NEW_ODRDERS table would not get created because the DEFAULT value cannot be specified in the column definition.

The NEW_ODRDERS table would get created and only the NOT NULL constraint defined on the specified columns would be passed to the new table.

The NEW_ODRDERS table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.

The NEW_ODRDERS table would get created and all the constraints defined on the specified columns in the ORDERS table would be passed to the new table.

NO.28 Examine the description or the BOOKS_TRANSACTIONS table:

FOR customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND cust credit_level !=NULL;

SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level IS NOT NULL
AND due_amount IS NOT NULL;

SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level <> NULL
AND due_amount <> NULL;

SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL
AND cust_credit_limit IS NOT NULL;

SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND due_amount !=NULL;

NO.29 You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID- must be able to contain a maximum of 12 alphanumeric characters and must uniquely identify the row EXECUTION_DATETIME- contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently? (Choose two.)

The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.

The EXECUTION_DATETIME must be of TIMESTAMP data type.

The EXECUTION_DATETIME must be of DATE data type.

The COMPONENT_IDmust be of ROWID data type.

The COMPONENT_IDmust be of VARCHAR2 data type.

The COMPONENT_IDcolumn must be of CHAR data type.

NO.30 View the exhibit and examine the structure of the CUSTOMERStable.

Which two tasks would require subqueries or joins to be executed in a single statement?

finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers

finding the average credit limit of male customers residing in ‘Tokyo’or ‘Sydney’

listing of customers who do not have a credit limit and were born before 1980

finding the number of customers, in each city, whose marital status is ‘married’.

listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city ‘Tokyo’.

NO.31 Examine the structure of the MEMBERS table:

You want to display details of all members who reside in states starting with the letter A followed by exactly one character.
Which SQL statement must you execute?

SELECT * FROM MEMBERS WHERE state LIKE ‘%A_’;

SELECT * FROM MEMBERS WHERE state LIKE ‘A_’;

SELECT * FROM MEMBERS WHERE state LIKE ‘A_%’;

SELECT * FROM MEMBERS WHERE state LIKE ‘A%’;

NO.32 View the Exhibit and examine the structure of the EMPtable which is not partitioned and not an index-organized table. (Choose two.)

Evaluate this SQL statement:
ALTER TABLE emp
DROP COLUMN first_name;
Which two statements are true?

The FIRST_NAMEcolumn can be dropped even if it is part of a composite PRIMARY KEYprovided the CASCADEoption is added to the SQL statement.

The FIRST_NAMEcolumn would be dropped provided at least one column remains in the table.

The FIRST_NAMEcolumn would be dropped provided it does not contain any data.

The drop of the FIRST_NAMEcolumn can be rolled back provided the SET UNUSEDoption is added to the SQL statement.

NO.33 Examine the data in the ORD_ITEMStable:

Evaluate this query:

Which statement is true regarding the result?

It returns an error because the HAVINGclause should be specified after the GROUP BYclause.

It returns an error because all the aggregate functions used in the HAVINGclause must be specified in the SELECT list.

It displays the item nos with their average quantity where the average quantity is more than double the minimum quantity of that item in the table.

It displays the item nos with their average quantity where the average quantity is more than double the overall minimum quantity of all the items in the table.

NO.34 View the Exhibit and examine the details of PRODUCT_INFORMATION table.

You have the requirement to display PRODUCT_NAME from the table where the CATEGORY_ID column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088;
Which statement is true regarding the execution of the query?

It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.

It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.

It would execute and the output would display the desired result.

It would execute but the output would return no rows.

NO.35 Examine the structure of the BOOKS_TRANSACTIONStable:

You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM BOOKS_TRANSACTIONS;

SELECT member_id ‘MEMBER ID’, due_date ‘DUE DATE’, ‘$2 AS LATE FEE’ FROM BOOKS_TRANSACTIONS;

SELECT member_id AS “MEMBER ID”, due_date AS “DUE DATE”, ‘$2’ AS “LATE FEE” FROM BOOKS_TRANSACTIONS;

SELECT member_id AS “MEMBER ID”, due_date AS “DUE DATE”, $2 AS “LATE FEE” FROM BOOKS_TRANSACTIONS;

NO.36 Examine this SQL statement:

Which two are true?

All existing rows in the ORDERS table are updated

The subquery is executed for every updated row in the ORDERS table

The subquery is executed before the UPDATE statement is executed

The subquery is not a correlated subquery

The UPDATE statement executes successfully even if the subquery selects multiple rows

NO.37 Examine the description of the EMPLOYERS table:

Examine these requirements:
Disable the manager ID and salary of the lowest paid employees for that manager.
Exclude anyone whose manager is not known.
Exclude any managers where the minimum salary is 6000 or less.
Sort the output by minimum salary with the highest salary shown first.
Which statement will do this?

SELECT manager_id, MTN(salary)
FROM employees
WHERE manager_ id IS NOT NULL
GROUP BY manager_id
HAVING MlN (salary) > 6000
ORDER BV MlN (salary);

SELECT managar_id, MIN (salary)
FROM employees
HAVING MIN(salary) > 6000
WHERE manager_id IS NOT NULL
GROUP BY manager_id
ORDER BY MTN(salary) DESC;

SELECT manager_id, HTN(salary)
FROM employees
WHERE manager_id IS NOT NULL
HAVING MIN (salary) > 6000
GROUP BY manager_id
ORDEU BY MIN (salary) DESC;

SELECT manager_id, MIN(salary)
FROM employees
WHERE manager_id IS NOT NULL
AND MIN(salary) > 6000
GROUP BY manager_id
ORDER BY MlN (salary) DESC;

NO.38 View the Exhibit and examine the details of the ORDER_ITEMS table.

Evaluate the following SQL statements:
Statement 1:
SELECT MAX(unit_price*quantity) “Maximum Order”
FROM order_items;
Statement 2:
SELECT MAX(unit_price*quantity) “Maximum Order”
FROM order_items
GROUP BY order_id;
Which statements are true regarding the output of these SQL statements? (Choose all that apply.)

Statement 2 would return multiple rows of output.

Both statements would ignore NULL values for the UNIT_PRICE and QUANTITY columns.

Statement 1 would not return give the same output.

Both the statements would give the same output.

Statement 1 would return only one row of output.

NO.39 Which two tasks can be performed by using Oracle SQL statements?

changing the password for an existing database user

connecting to a database instance

querying data from tables across databases

starting up a database instance

executing operating system (OS) commands in a session

You should also know:

Recertification is required every three years. In general, this course takes 9 weeks to complete, but it depends on the person who is taking this course. Oracle 1Z0-071 Dumps cover all questions of 1Z0-071. In order to tune your 1Z0-071 certification after you have completed the course, you must pass Oracle’s Exam Retake Retrieval Tool twice.

The Exam Retake Retrieval Tool was originally designed for people who have already passed a 1Z0-102 exam and want to retake the exam for a better score. You will need a separate username and password in order to access this tool from any computer. The process of using the tool consists of signing into your Oracle account then asking for your name in order to get your username and password. After you get your username and password, you connect to the Retake Retrieval Tool. When you are connected to the tool, it will show all of your 1Z0-071 exam histories. You will then see a link where you can retrieve your exam history.

Once retrieved, run the exam for at least two full cycles. The first cycle is 3 hours long and the second cycle is 5 hours long. After running each cycle at least once, you should then mark or unmark questions that could potentially be on future exams that appear on the exam itself. Then, after the first cycle is completed, you can go back to the Retook Retrieval Tool and you will see that the length of the exam has increased. Once you complete this process twice, you will be able to take your final exam for the 1Z0-071 certification.

1z0-071 Questions PDF [2023] Use Valid New dump to Clear Exam: https://www.actualtorrent.com/1z0-071-questions-answers.html

Ace 1z0-071 Certification with 305 Actual Questions [Q16-Q39]

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